Question

The dimension of a solid iron cuboid are 4.4×2.6×1.0 meter. It is melted and recast into a hollow cylindrical pipe of 30m inner radius and thickness 5 centimetre. Find the length of the pipe.

Answer 1

Solution:-

Let the inner and outer radius of the cylindrical pipe be 'r' and 'R' respectively.

Inner radius 'r' = 30 cm

Thickness = 5 cm

Outer radius 'R'= 30 + 5 = 35 cm

Length of the cuboid = 4.4 m or 440 cm
Breadth of the cuboid = 2.6 m or 260 cm
Height of the cuboid = 1 m or 100 cm

Here,
Volume of the cuboid = Volume of the cylindrical pipe
⇒ 440*260*100 = π(R² - r²)h
⇒ 440*260*100 = 22/7*(35² - 30²)*h
⇒ 11440000 = 22/7*(1225 - 900)*h
⇒ 11440000 = 22/7*325*h
⇒ h = (11440000*7)/(325*22)
⇒ h = 80080000/7150
⇒ h = 11200 cm
Or 112 m
So, the length of the pipe is 112 m

Answer.

Answer 2

Answer:

answer is above

hit thanks button is you are from St kabeer academy and doing home assignment !