The dimension of an open bix are 50 cm and 40 cm and 23 cm.Its thickness is 3 cm
Answers
Answered by
2
50*40*23)-(46*36*21)
=(2*25*2*20*23)-(2*23*2*18*21)
=(4*25*20*23)-(4*23*18*21)
=4*23*(25*20-18*21)
=4*23*(500-378)
=4*23*122 cm^3
each cm^3 it's of 1/2 gm weight, so total weight of the box is
=4*23*122/2=2*23*122=46*122=5612gms...6 years agoHelpfull: Yes(24) No(1)
if you want it's simply
volume of metal is external volume of cube-internal volume of cube=(50*40*23)-(46*36*21)=46000-34776
=11224 cm^3
weight of the metal=11224 cm^3 * 0.5 gm/cm^3 =5612 gm or 5.612 kg
=(2*25*2*20*23)-(2*23*2*18*21)
=(4*25*20*23)-(4*23*18*21)
=4*23*(25*20-18*21)
=4*23*(500-378)
=4*23*122 cm^3
each cm^3 it's of 1/2 gm weight, so total weight of the box is
=4*23*122/2=2*23*122=46*122=5612gms...6 years agoHelpfull: Yes(24) No(1)
if you want it's simply
volume of metal is external volume of cube-internal volume of cube=(50*40*23)-(46*36*21)=46000-34776
=11224 cm^3
weight of the metal=11224 cm^3 * 0.5 gm/cm^3 =5612 gm or 5.612 kg
Similar questions
Social Sciences,
7 months ago
English,
7 months ago