The dimension of Mr Narula's bedroom
is 8 m x 7m x 5 m. It has two windows, V
each measuring 2m x 1m and one door
measuring 3 m x 1m. Find the cost of
white washing the room at 50 per
square metre.
answer = ₹ 7150
Answers
Step-by-step explanation:
Given ,
Dimension of Bedroom =8m×7m×5m
Area of room = area of cuboid =2(lb+bh+hl)
=2(8×7+7×5+5×8)=2(56+35+40)=2(146)
Area of room =292 m square
Area of window = Area of rectangle =l×b
=2×1=2 m square
There are 2 windows, total area =2×2=4 ms square
Area of door =l×b=3×1=3 m square.
∴ Area pf whitewashing room = Area room − [area of door + area of window]
=292−[4+3]=292−7
=285 sq meter
Cost of whitewashing (at 50 per square meter )=285×50
Cost of whitewashing =14,250 Rupees
Answer:
₹9,950
Step-by-step explanation:
Given, dimensions of room is 8m ×7m ×5m,
two windows of dimensions 2m× 1m and door of dimensions 3m ×1m.
Area of door= 3m×1m= 3m^2
Area of two windows= 2( 2m × 1m)= 4m^2
Area of roof= 8m×7m=56m^2
Curved surface area of cuboid(room)=2h(l+b)
=2×5m(8m+7m)
=10m(15m)
=150m^2
We know that whitewashing is done only for four walls and the roof
So area of whitewashing= (curved surface area of room + area of roof) - (area of door + area of two windows)
=(150m^2+56m^2) -(3m^2+4m^2)
= 206m^2 - 7m^2
= 199m^2
Area of white washing = 199m^2
cost of whitewashing = 199m^2×50
= ₹9,950