Question

The dimensional formula of magnetic flux are

Answer 1

F=qvBsinθF=qvBsin⁡θ

B=FqvsinθB=Fqvsin⁡θ

[B]=[MLT−2][LT−1][AT]=MLOT−2A−1[B]=[MLT−2][LT−1][AT]=MLOT−2A−1

Hence Magnetic flux = BA

=[MT−2A−1][L2]=[MT−2A−1][L2]

=ML2T−2A−1=ML2T−2A−1