the dimensions of a closed cuboidal box are in the ratio 5:4:3. of the total surface are is 0.94 m^2,find the dimensions of the box.
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Let one side is x. So
2(5x*4x +4x*3x +5x *3x)
=2(47x)=0.94
47x=0.94/2
x=0.47/47
x=0.1m
5x=0.5m
3x=0.3m
4x=0.4m
2(5x*4x +4x*3x +5x *3x)
=2(47x)=0.94
47x=0.94/2
x=0.47/47
x=0.1m
5x=0.5m
3x=0.3m
4x=0.4m
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