Question

the dimensions of a closed cuboidal box are in the ratio 5:4:3. of the total surface are is 0.94 m^2,find the dimensions of the box.​

Answer 1

Answer:

0.05 m

0.04 m

0.03 m

Step-by-step explanation:

let the length of the box be 5x

let the breadth of the box be 4x

let the height of the box be 3x

total surface area of a Cuboid is 2(lb + bh + lh)

2[5x(4x) + 4x(3x) + 5x(3x)] = 9400 cm2

2[20x^2 + 12x^2 + 15x^2] = 9400 cm2

2(47x^2) = 9400 cm2

94x^2 = 9400 cm2

x^2= 100

x = 10

length of the box = 5(10) = 50 cm

breadth of the box = 4(10) = 40 cm

height of the box = 3(10) = 30 cm

hope this helps

Answer 2

Answer:

Given -

Let the dimensions of Closed cuboidal box be -

Length - 5x,

Breath -4x,

Height -3x

TSA of Cuboid = 2 (lb + bh + lh)

0.94m² = 2 (5x × 4x + 4x × 3x + 3x × 5x)

9400= 2 × 47 x²

9400= 94x²

9400/94=x²

100=x²

√100=x

x=10 cm

Length = 5×10 = 50 cm

Breath = 4×10 = 40 cm

Height = 3×10 =30cm

These are the dimensions of the box = 50cm,40cm,30cm

I converted 9400 m² into cm to make easier calculation

Now .you can convert dimensions into metres .

that will be

Length = 0.5 m

Breath = 0.4 m

Height = 0.3m