The dimensions of a cuboid are in the ratio 1 : 2 : 3 , and its TSA is 88m2 . Find its volume.
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☣Let the dimensions be x
so :- 1x , 2x , 3x are respectively length, breadth and height of cuboid
TSA of cuboid =
![= 2(lb \: + bh + hl) = 2(lb \: + bh + hl)](https://tex.z-dn.net/?f=+%3D+2%28lb+%5C%3A+%2B+bh+%2B+hl%29)
88 = 2 { ( x × 2x) + (2x × 3x) + (3x × x) }
44 = 2x² + 6x² + 3x²
44 = 11x²
4 = x²
√4 = x
2 = x
⭐ So,
☣ length ( l ) = x = 2m
☣ Breadth ( b ) = 2x = 2×2 = 4m
☣ Height ( h ) = 3x = 3 × 2 = 6m
☢ Volume of Cuboid = l × b × h
= 2 × 4 × 6
= 48m³
So,
➡ the volume of cuboid = 48m²
@Altaf
so :- 1x , 2x , 3x are respectively length, breadth and height of cuboid
TSA of cuboid =
88 = 2 { ( x × 2x) + (2x × 3x) + (3x × x) }
44 = 2x² + 6x² + 3x²
44 = 11x²
4 = x²
√4 = x
2 = x
⭐ So,
☣ length ( l ) = x = 2m
☣ Breadth ( b ) = 2x = 2×2 = 4m
☣ Height ( h ) = 3x = 3 × 2 = 6m
☢ Volume of Cuboid = l × b × h
= 2 × 4 × 6
= 48m³
So,
➡ the volume of cuboid = 48m²
@Altaf
Answered by
10
Hello.............. ^_^
Here is your answer......
Given :-
dimensions of a cuboid are in ratio 1:2:3
total surface area is 88m square.
let,
length be 3x m
breath be 2x m
height be 1x m
![total \: \: surface \: \: area = 88 {m}^{2} \\ \\ = > 2(length \times breadth + breadth \times height + height \times length) = 88 \\ \\ = > 2(3x \times 2x + 2x \times 1x + 1x \times 3x) = 88 \\ \\ = > 2(6 {x }^{2} + 2 {x}^{2} + 3 {x}^{2} ) = 88 \\ \\ = > 2(11 {x}^{2} ) = 88 \\ \\ = > 11 {x}^{2} = \frac{88}{2 } \\ \\ (88 \div 2 = 44) \\ \\ = > 11 {x }^{2} = 44 \\ \\ = > {x}^{2} = \frac{44}{11} \\ \\ (44 \div 11 = 4) \\ \\ = > {x}^{2} = 4 \\ \\ = > x = \sqrt{4 } \\ \\ = > x = 2 total \: \: surface \: \: area = 88 {m}^{2} \\ \\ = > 2(length \times breadth + breadth \times height + height \times length) = 88 \\ \\ = > 2(3x \times 2x + 2x \times 1x + 1x \times 3x) = 88 \\ \\ = > 2(6 {x }^{2} + 2 {x}^{2} + 3 {x}^{2} ) = 88 \\ \\ = > 2(11 {x}^{2} ) = 88 \\ \\ = > 11 {x}^{2} = \frac{88}{2 } \\ \\ (88 \div 2 = 44) \\ \\ = > 11 {x }^{2} = 44 \\ \\ = > {x}^{2} = \frac{44}{11} \\ \\ (44 \div 11 = 4) \\ \\ = > {x}^{2} = 4 \\ \\ = > x = \sqrt{4 } \\ \\ = > x = 2](https://tex.z-dn.net/?f=total+%5C%3A++%5C%3A+surface+%5C%3A++%5C%3A+area++%3D+88+%7Bm%7D%5E%7B2%7D++%5C%5C+%5C%5C++%3D++%26gt%3B+2%28length+%5Ctimes+breadth+%2B+breadth+%5Ctimes+height+%2B+height+%5Ctimes+length%29+%3D+88+%5C%5C++%5C%5C++%3D++%26gt%3B+2%283x+%5Ctimes+2x+%2B+2x+%5Ctimes+1x+%2B+1x+%5Ctimes+3x%29+%3D+88+%5C%5C++%5C%5C++%3D++%26gt%3B+2%286+%7Bx+%7D%5E%7B2%7D+%2B+2+%7Bx%7D%5E%7B2%7D+%2B+3+%7Bx%7D%5E%7B2%7D+++%29+%3D+88+%5C%5C++%5C%5C++%3D++%26gt%3B+2%2811+%7Bx%7D%5E%7B2%7D+%29+%3D+88+%5C%5C++%5C%5C++%3D++%26gt%3B+11+%7Bx%7D%5E%7B2%7D++%3D++%5Cfrac%7B88%7D%7B2+%7D++%5C%5C++%5C%5C+%2888+%5Cdiv+2+%3D+44%29+%5C%5C++%5C%5C++%3D++%26gt%3B+11+%7Bx+%7D%5E%7B2%7D++%3D+44+%5C%5C++%5C%5C++%3D++%26gt%3B++%7Bx%7D%5E%7B2%7D++%3D++%5Cfrac%7B44%7D%7B11%7D++%5C%5C++%5C%5C+%2844+%5Cdiv+11+%3D+4%29+%5C%5C++%5C%5C++%3D++%26gt%3B++%7Bx%7D%5E%7B2%7D++%3D+4+%5C%5C++%5C%5C++%3D++%26gt%3B+x+%3D++%5Csqrt%7B4+%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+x+%3D+2)
length = 3x = 3 X 2 = 6m
breadth = 2x = 2 X 2 = 4m
height = 1x = 1 X 2 = 2m
Volume of cuboid = length X breadth X height
![= 6 \times 4 \times 2 \: \: {m}^{3} \\ = 48 {m}^{3} = 6 \times 4 \times 2 \: \: {m}^{3} \\ = 48 {m}^{3}](https://tex.z-dn.net/?f=+%3D+6+%5Ctimes+4+%5Ctimes+2++%5C%3A++%5C%3A++%7Bm%7D%5E%7B3%7D+%5C%5C++%3D+48+%7Bm%7D%5E%7B3%7D+)
Hope it helps............... ^_^
Here is your answer......
Given :-
dimensions of a cuboid are in ratio 1:2:3
total surface area is 88m square.
let,
length be 3x m
breath be 2x m
height be 1x m
length = 3x = 3 X 2 = 6m
breadth = 2x = 2 X 2 = 4m
height = 1x = 1 X 2 = 2m
Volume of cuboid = length X breadth X height
Hope it helps............... ^_^
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