Question

The dimensions of a cuboid are in the ratio 3:2:2 and the lateral surface area of the cuboid is 200 m^2 . The outer surface of the cuboid is painted with enamel at the rate of rupees 10 per m^2. Find the total cost of painting the outer surface of the cuboid.

PLEASE HELP ME IN THIS QUESTION I WILL MARK BRAINLIST

Answer 1

Step-by-step explanation:

let the dimension of cuboid be 3x 2x and 2x

lateral surface area of cuboid = 200m^2

2(l+b)h. = 200

2(3x+2x) × 2x. = 200

2 × 5x × 2x. = 200

20x^2 = 200

x^2 = 200÷20

x^2 = 10

x = √10

total surface area of cuboid= 2(lb+bh+hl )

= 2 ( 3√10*2√10 + 2√10*2√10+2√10*3√10)

total surface area of cuboid= 2(60+40+60)

= 2 (160)

= 320m^2

cost of painting 1msquare = rupees 10

therefore cost of painting 320msquare = 10× 320

= rupees 3,200