The dimensions of a cuboid are in the ratio of 1:2:3 and its total surface area is 88m.find the dimensions.
Answers
Correct Question:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
The dimensions of a cuboid are in the ratio of 1:2:3 and its total surface area is 88m. Find the dimensions.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Given:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
- Dimensions of cuboid are given in the ratio of 1 : 2 : 3.
- Total surface area of the cuboid = 88 m
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
To find:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Dimensions of the cuboid.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Solution:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Let the dimensions be x, 2x and 3x in metres.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
We know that,
Total surface area of a cuboid = 2( lb + bh + lh)
So,
2(x × 2x + 2x × 3x + x × 3x) = 88
2(2x + 6x + 3x) = 88
2 × 11x = 88
22x = 88
x = 4
x = 2
x = 2 m
Now, its dimension = 2x = 2 × 2 = 4
3x = 3 × 2 = 6.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Thus, the dimensions of the cuboid are 2 m, 4 m and 6 m respectively.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
More formulas:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
For cuboid:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Total surface area of the cuboid = 2(lb + bh + lh)
Lateral surface area of the cuboid = 2(l + b)h
Diagonal of the cuboid
Length of all 12 edges of the cuboid = 4(l + b + h)
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
For cube:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Total surface area of the cube = 6l
Lateral surface area of the cube = 4l
Diagonal of the cube
Length of all 12 edges of the cube = 12 l
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Correct Question:
The dimensions of a cuboid are in the ratio of 1:2:3 and its total surface area is 88m².Find the dimensions.
Given:
Ratio of Dimensions of 1 : 2 : 3.
T.S.A of the cuboid = 88 m²
To find :-
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
What is the Dimensions of the cuboid ?
Solution:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Consider the dimensions be x, 2x and 3x in metres.
Applying the formula :-
Total surface area of a cuboid = 2( lb + bh + lh)
Substituting the values in the above formula :-
2(x × 2x + 2x × 3x + x × 3x) = 88
2(2x + 6x + 3x) = 88
2 × 11x = 88
22x = 88
x = 4
x = 2
= x = 2 m
Therefore ,
Dimension
= 2x = 2 × 2 = 4
3x = 3 × 2 = 6.
So the dimensions are :- ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
2 m, 4 m and 6 m .
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Additional Information :
❥ Perimeter of Rectangle = 2( L + B )
❥ Perimeter of square = 4 × Side
❥ Perimeter of triangle = AB + BC + CA
❥ Area of Rectangle = L × B
❥ Area of Square = ( side ) ²
❥ Area of Rhombus = Product of Diagonal/2.
❥ Area of Parallelogram = Base × Height.
❥ Area of triangle = 1/2 × base × height.
❥ Total surface area of the cuboid = 2(lb + bh + lh)
❥ Lateral surface area of the cuboid = 2(l + b)h
❥ Length of all 12 edges of the cuboid = 4(l + b + h)⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
❥Total surface area of the cuboid = 2(lb + bh + lh)
❥Lateral surface area of the cuboid = 2(l + b)h
❥ Diagonal of the cuboid = { l²+ b²+ h²}
❥ Length of all 12 edges of the cuboid = 4(l + b + h)
❥Total surface area of the cube = 6l
❥Lateral surface area of the cube = 4l
❥Diagonal of the cube
❥ Length of all 12 edges of the cube = 12 l
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀