Question

The dimensions of a cuboid shaped overhead tank are 24m × 10m × 6m. If the full tank is being drained with a pipe pouring 100 L water per second, then how much time will it take to fill the tank?​

Answer 1

Answer:

The dimensions of a cuboid shaped overhead tank are 24m 10m 6m. If the full tank is being drained with a pipe pouring 100 L per second. 14,400 sec / (60 × 60) = 4 hours. Therfore, 4 hours of time is required to take to empty the tank.

Answer 2

$\rm\dag\large\underline{Question: }$

The dimensions of a cuboid shaped overhead tank are 24m × 10m × 6m. If the full tank is being drained with a pipe pouring 100 L water per second, then how much time will it take to fill the tank ?

$\rm\dag\large\underline{Given: }$

Cuboid dimension .

Length = 24 m.

Breadth = 10 m.

Height = 6 m.

$\rm\dag\large\underline{To\: find: }$

Time taken to fill the tank.

$\rm\dag\large\underline{Answer: }$

$\rm\large \red{ 4 \: hours \: .}$

$\rm\dag\large\underline{Soluation: }$

Volume of cuboid

$\rm\bf \mapsto \: \: \large{l \: \times \: b \: \times \: h }$

$\rm\rightarrow\large{ \: 24 \: \times \: 10 \: \times 6}$

$\rm\rightarrow\large{ \:1440 \: {m}^{3} }$

$\rm\large \pink{ {1 \: m}^{3} \: = 1000 \: L }$

$\rm\large{ {1400 \: m}^{3} \: = x }$

$\rm\large {x = \: \frac{1000 \: \times \: 1400}{l} } \\ \\ \rm \large \rightarrow \: { \: x \: = \: 1440000 \: \:L }$

$\rm\large \bf{ 100 \: L \rightarrow1 \: sec }$

$\rm\large { 1440000 \: L \: \mapsto \: x }$

$\rm\large { \: x \: = \: \frac{1 \: \times \: 1440000}{100} \: } \: \\ \\ \rm\large = \: 14400 \: second.$

$\rm\large \pink {So, } Time \: taken\: to \: fill \: the \: tank \: \\ = \rm \bf 14400 \: second \: \: = \: 240 \: min \: \\ \rm \bf \: = 4 \: hours \: .$