The dimensions of a cuboidal box are 6 m×400 cm×1.5 m. Find the cost of painting it's entire outer surface at the rate of ®22 per m²
Answers
Given:
Length of the cuboidal box = 6 meters
Breadth of the cuboidal box = 400 cm
Converting the Breadth to meter by dividing by 100 we get:
= 400 / 100
= 4 meters
Height of the cuboidal box = 1.5 meters
To Find:
The Cost Required For Painting Entire Outer Surface At The Rate Rupees 22 per m^2.
Calculating:
The formula that is used to find the total surface area of a cuboid:
= 2(lb + lh + bh)
Substituting all the values known to us in this formula we get:
= 2((6)(4) + (6)(1.5) + (4)(1.5))
= 2(24 + 9 + 6)
= 2(30 + 9)
= 2(39)
= 78 meter square
Therefore, the total surface area of the cuboidal box is 78 m^2.
Calculating the cost of painting the outer surace at the rate of Rupees 22 per m^2:
= 22 x 78
= Rs. 1716
Therefore, the cost of painting the entire outer surface of the cuboidal box is Rupees 1716.