The dimensions of a cuboidal box are in ratio 5 : 3 : 2 and its total surface area is 2088 cm ² find dimensions
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here is the solution.
let the length be=5y
breadth= 3y
height= 2y
tsa=2088
tsa= 2(lb+bh+hl)
2088=2(5y × 3y + 3y × 2y + 2y × 5y)
2088÷2= 15y² + 6y² + 10y²
1044= 31y²
y²= 1044×31
y²= 33.677
y=5.80cm
l= 5y= 5 x 5.80=
b=3y= 3 x 5.80=
h=2y=2 x 5.80=
u can find out the values
and before doing the sum pls check if my calculations are wrong
i might have made a mistake somewhere.
hope i could help u
let the length be=5y
breadth= 3y
height= 2y
tsa=2088
tsa= 2(lb+bh+hl)
2088=2(5y × 3y + 3y × 2y + 2y × 5y)
2088÷2= 15y² + 6y² + 10y²
1044= 31y²
y²= 1044×31
y²= 33.677
y=5.80cm
l= 5y= 5 x 5.80=
b=3y= 3 x 5.80=
h=2y=2 x 5.80=
u can find out the values
and before doing the sum pls check if my calculations are wrong
i might have made a mistake somewhere.
hope i could help u
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