Question

The dimensions of a cuboidal tin box are 30cm ^ 40cm ^ 50cm. Find the tin required for 20 such boxes if the cost of tin sheet is Rs 25 per square meter​

Answer 1

Step-by-step explanation:

As we know that,

Surface area of cuboid =2(lb+bh+hl)

Therefore,

Surface area of 1 tin box

=2(30×40+40×50+50×30)

=2×(1200+2000+1500)

=9400cm

2

Surface area of 20 tin box =20×9400=188000cm

2

=18.8m

2

Given that the cost of the tin sheet is R.20 per square meter.

Therefore,

Cost of tin required for 20 tin boxes =20×18.8=Rs.376

Answer 2

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Step-by-step explanation:

As we know that,

Surface area of cuboid =2(lb+bh+hl)

Therefore,

Surface area of 1 tin box

=2(30×40+40×50+50×30)

=2×(1200+2000+1500)

=9400cm2

Surface area of 20 tin box =20×9400=188000cm2

=18.8m2

Given that the cost of the tin sheet is R.25per square meter.

Therefore,

Cost of tin required for 20 tin boxes =25×18.8

=Rs.470