Question

The dimensions of a cuboidal tin box are 30cm ^ 40cm ^ 50cm. Find the tin required for 20 such boxes if the cost of tin sheet is Rs 25 per square meter​

Answer 1

Answer:

Surface area of cuboid =2(lb+bh+hl)

Therefore,

Surface area of 1 tin box

=2(30×40+40×50+50×30)

=2×(1200+2000+1500)

=9400cm

2

Surface area of 20 tin box =20×9400=188000cm

2

=18.8m

2

Given that the cost of the tin sheet is R.20 per square meter.

Therefore,

Cost of tin required for 20 tin boxes =20×18.8=Rs.376

Step-by-step explanation:

answer is above

hope it helps you

Answer 2

2(lb+bh+hl)

Therefore,

surface area of 1 tin box

= 2(30×40+40×50+50×30)

=2×(1200+2000+1500)

=9400cm^2

surface area of 20 tin box

=20×9400=188000cm^2

=18.8m^2

given that the cost of the tin sheet is Rs.20 per square meter

Therefore, cost of tin required for 20 tin boxes

=Rs.376.