Question

the dimensions of a field are 15 m by 12 m. a pit 7.5 long , 6 m wide and 1.5 m deep is dug at one corner of the field. the earth removed is evenly spread over the remaining area of the field. calculate the rise in the level of the field.
its urgent !!

Answer 1

volume of earth in pit=7.5*6*1.5
                                  =67.5 m cube
let height of field increased be x
Therefore,
when spread across the field, volume remains same but dimensions change
67.5=15*12*x
x=67.5/180
x=0.375m
therefore rise in level is 0.375m or 375cm

Answer 2

Answer:

Step-by-steGiven, Dimension of the field = 15 m × 12 m

Dimension of the pit = 8 m × 2.5m × 2m

Volume of earth removed from the pit = 8m × 2.5 m × 2 m = 40 m3

Area of the remaining field

= Area of the field – Area of the pit

= 15 m × 12 m – 8 m × 2.5 m

= 160 m2

Since, the earth removed is evenly spread over the remaining area of the field.

∴ Increase in level of remaining field × Area of remaining field  = Volume of earth removed from the pit

Increase in level of remaining field = 40/160 =0.25m