Question

The dimensions of a field are 15 m by 12 m. A pit 7.5 m long, 6 m wide and 1.5 m deep is dug at one corner of the field. The earth removed is evenly spread over the remaining area of the field. Calculate the rise in the level of the field​

Answer 1

Answer:

Volume of earth in pit=7.5*6*1.5

=67.5 m cube

let height of field increased be x

Therefore,

when spread across the field, volume remains same but dimensions change

67.5=15*12*x

x=67.5/180

x=0.375m

therefore rise in level is 0.375m or 375cm