Question

The dimensions of a field are 15m by 12m.A pit 8m long,2.5m wide and 2m deep is dug in one corner of the field and the earth removed is evenly spread over the remaining area of the field, calculate by how much is the level of the field raised.

Answer 1

Given, Dimension of the field = 15 m × 12 m

Dimension of the pit = 8 m × 2.5m × 2m

Volume of earth removed from the pit = 8m × 2.5 m × 2 m = 40 m3

Area of the remaining field

= Area of the field – Area of the pit

= 15 m × 12 m – 8 m × 2.5 m

= 160 m2
Since, the earth removed is evenly spread over the remaining area of the field.

∴ Increase in level of remaining field × Area of remaining field  = Volume of earth removed from the pit

Increase in level of remaining field = 40/160 =0.25m

Answer 2

Step-by-step explanation:

Dimension of the field = 15 m × 12 m

Dimension of the pit = 8 m × 2.5m × 2m

Volume of earth removed from the pit = 8m × 2.5 m × 2 m = 40 m3

Area of the remaining field

= Area of the field – Area of the pit

= 15 m × 12 m – 8 m × 2.5 m

= 160 m2

Since, the earth removed is evenly spread over the remaining area of the field.

∴ Increase in level of remaining field × Area of remaining field  = Volume of earth removed from the pit

Increase in level of remaining field = 40/160 =0.25m