Question

The dimensions of a hall is 10 m × 9 m × 8 m. Find the cost of white washing the walls and ceiling at the rate of ₹8.50 per m2

Answer 1

Given:

The hall is in the shape of a cuboid.

Length of the cuboid = 10 meters

Breadth of the cuboid = 9 meters

Height of the cuboid = 8 meters

To Find:

The cost of white washing the walls and ceiling at theater at Rupees 8.50 per m^2.

Calculating:

Formula used to find the surface area of the hall:

= 2h(l + b) + lb

Substituting all the values known to us in this formula we get:

= 2 x 8(10 + 9) + 10 x 9

= 16(19) + (90)

= 304 + 90

=  394 m^2

Therefore, the surface area of the hall is 394 m^2.

Calculating the cost of white washing at rupees 8.50 per m^2:

= 394 x 8.50

= Rs. 3349

Therefore, the cost of white washing the walls and ceiling at the rate of Rupees 8.50 per m^2 is Rupees 3349.

Answer 2

Step-by-step explanation:

here is the step by step explanation