Question

The dimensions of a hall is 10 mx9m x 8 m. Find the cost of white washing the
walls and ceiling at the rate of 78.50 per m^2​
​

Answer 1

Answer:

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The dimensions of a cuboidal hall are 10 m × 9 m × 8 m

To finD :--

Cost of White Washing the Walls and Ceiling

There are two approaches to solve the given question

We find the Total Surface Area of the hall and subtract the area of floor from the latter,which would give us the area required to be painted

We can find the Lateral Surface Area of tne hall and add the area of the ceiling,which would give us the area to be painted

Now,

Length,l = 10 m

Breadth,b = 9 m

Height,h = 8 m

Total Area to be PainteD

$\implies \sf LSA + Area \ of \ Ceiling \\ \\ \implies \sf 2h(l +b) + (l \times b) \\ \\ \implies \sf 2(8)(10 + 9) + (10 \times 9) \\ \\ \implies \sf 394 {m}^{2}$

The total area to be painted is 394 m²

Now,

The cost of painting one m² is 78.50 rupees

The cost of painting 394 m² would be :

$\implies \: \sf \: 394 \times 78.50 \\ \\ \implies \: \sf \: Rs \ 30929 \:$

Answer 2

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