Question

the dimensions of a hall is 10m×9m×8m. find the cost of white washing the walls and ceiling at the ratr of rupees 8.50per sq.m.​

Answer 1

Answer:

Rs 3349

Step-by-step explanation

GIVEN : LENGTH = 10 m

breadth : 9 m

height : 8 m

CURVED SURFACE AREA =2(l+b)h

2(10+9)8

2*19*8

19*16

304 m²

AREA OF CEILING

L*B

10*9

90

TOTAL AREA= 304+90

                      =394 M²

COST= 394*8.5

         Rs 3349

Answer 2

$\huge{\underline{\mathfrak{QuestioN}}}$ :

The dimensions of a hall are 10 m × 9 m × 8 m. Find the cost of white washing the walls and ceiling at the rate of rupees 8.50 per m² ?

                                                GiveN :

• The dimensions of the hall = 10 m × 9 m × 8 m.
• Cost of white washing per m² is 8.50 rupees.

                                              To FinD :

• The cost of white washing the walls and ceiling.

We have to find the lateral surface area, the lateral surface area of a cuboid is 2 × h ×  ( l + b ) .

             Now, Area of four walls  =  2 × h ×  ( l + b )

                              = 2 × 8 ( 10 + 9 )

                              =  304 m².

To find the area of the ceiling, we have to find the area of the rectangle. We know that the area of a rectangle is  l × b .

             Area of the ceiling =   l × b

                              = 10 × 9

                              = 90 m².

Now, we have to find the total area of white washing, which'll be found if we add the area of the ceiling and the lateral surface area of the hall.

Total area of white washing = 304 + 90

                                               = 394 m².

Given that, cost of white washing per m² = 8.50 rupees.

So the total cost of white washing = 394 × 8.50

                                                        = Rs. 3349.

Therefore, the total cost of white washing the walls and the ceiling at the rate of rupees 8.50 per m² is Rs. 3349