The dimensions of a hall is 10m×9m×8m.Find the cost of white washing the walls and ceiling at the rate of ₹8.50per m²
Answers
Answer:
Step-by-step explanation:
The hall is in the shape of a cuboid.
Length of the cuboid = 10 meters
Breadth of the cuboid = 9 meters
Height of the cuboid = 8 meters
To Find:
The cost of white washing the walls and ceiling at theater at Rupees 8.50 per m^2.
Calculating:
Formula used to find the surface area of the hall:
= 2h(l + b) + lb
Substituting all the values known to us in this formula we get:
= 2 x 8(10 + 9) + 10 x 9
= 16(19) + (90)
= 304 + 90
= 394 m^2
Therefore, the surface area of the hall is 394 m^2.
Calculating the cost of white washing at rupees 8.50 per m^2:
= 394 x 8.50
= Rs. 3349
Therefore, the cost of white washing the walls and ceiling at the rate of Rupees 8.50 per m^2 is Rupees 3349.
Answer:
(10*9*8)m = 720m
720×8.50 = 6120rs
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