Question

The dimensions of a metallic cuboid are 100 cm , 80 cm, and 64 cm. It is melted and recast into a cube. Find the surface area of the cube.

Answer 1

Hii mate..here is the solution.

.

the volume of the cuboid = the volume of the cube = 80×100×64 cm^3

so, the surface area of the cube is = 6a^2 = 6 × 80 × 80 cm^2

so the surface area of the cube is 80 cm^2... (Ans.)

Hope it will help you...

Answer 2

Answer:

$\huge{\pink{\boxed{\green{\sf{T.S.A\:OF\:CUBE=38400cm^{2}}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

▪GIVEN:

•Dimension of cubiod=100×80×64

▪To find:

•T.S.A of cube formed=?

$\to volume \: of \: cuboid = volume \: of \: cube \: formed \\ \to l \times b \times h = {a}^{3} \\ \to 100 \times 80 \times 64 = {a}^{3} \\ \to 512000 = {a}^{3} \\ \to a = \sqrt[3]{512000} \\ \to a = \sqrt[3]{8 \times 8 \times 8 \times 10 \times 10 \times 10} \\ \to a = 8 \times 10 \\ \to a = 80cm$

☆ We find the edge of cube

☆ According to the given question:

$\to T.S.A \: of \: cube = 6 {a}^{2} \\ \to T.S.A \: of \: cube = 6 \times {80}^{2} \\ \to T.S.A = 6 \times 6400 \\ { \pink{ \boxed{ \green{\to T.S.A = 38400 {cm}^{2} }}}}$

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