Math, asked by akanshayadav95288925, 4 months ago

the dimensions of a photograph are 25 CM × 22 CM what length of a wooden frame is needed to frame the photo​

Answers

Answered by shaktisrivastava1234
276

 \huge \fbox{Answer}

 \large \underline{ \underline{ \frak{ \color{red}Given::}}}

{ \mapsto \sf{Dimension \:  of  \:photograph=25cm×22cm}}

 \large \underline{ \underline{ \frak{ \color{re}To \:  find::}}}

{ \leadsto\sf{Length  \: of  \: wooden   \: frame \: required \: to \: frame \: the \: photo. }}

 \large \underline{ \underline{ \frak{ \color{pink}Concept \:  required::}}}

{ \implies\sf{Length  \: of  \: wooden   \: frame \:is \:  equal  \: to  \: the  \: perimeter  \: of  \: photograph. }}

 \large \underline{ \underline{ \frak{ \color{indigo}Formula \:  used::}}}

 \cdot{ \fbox{Perimeter of photograph=2(length + breadth)}}

 \large \underline{ \underline{ \frak{ \color{blue}According \:  to  \: Question::}}}

{ \dashrightarrow{ \sf{Perimeter  \: of  \: photograph=2(length + breadth)}}}

{ \dashrightarrow{ \sf{Perimeter  \: of  \: photograph=2(25cm + 22cm)}}}

{ \dashrightarrow{ \sf{Perimeter  \: of  \: photograph=2 \times 47cm}}}

{ \dashrightarrow{ \sf{Perimeter  \: of  \: photograph=94cm}}}

 \bf \underline{Hence, }

  \:  \:  \:  \:  \: \star{ \underline{ \fbox{Perimeter of photograph=2(length + breadth)}}}

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