The dimensions of a piece of iron in the shape of a cuboid are 270 cm, 100 cm and 64 cm. If it is melted and recast into a cube, then the surface area of the cube will be:
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24
given dimensions of the cuboid = 270cm × 100cm × 64cm
ATQ, the cuboid is melted and recasted into a cube.
therefore volume of the cuboid = volume of the cube
volume of the cuboid = l × b × h
= 270 × 100 × 64
= 1728000cm³
➡ volume of the cube = 1728000cm³
we know that side³ = volume of a cube
➡ side³ = 1728000cm³
➡ side = ³√1728000
➡ side = 120cm
the side of the cube is 120cm.
now it's surface area = 6 × side²
= 6 (120)²
= 6 × 14400
= 86400cm²
hence, the surface area of the cube is 86400cm².
Answered by
5
We know that volume of cuboid = volume of cube.
so,volume of cuboid =l×b×h
=270*100*64=1728000 cm^3.
volume of cube =1728000cm^3.
(side)^3=1728000cm^3
side= 3√1728000
side= 120 cm
Then,total surface area= 6l^2
6x 120^2 = 86400cm^2.
hope it helps.
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