Question

THE DIMENSIONS OF A RECTANGLE ARE 48 CM AND 14 CM. FIND THE LENGTH OF THE DIAGONAL OF THE RECTANGLE​

Answer 1

GIVEN:

• Length of the rectangle = 48 cm
• Breadth of the rectangle = 14 cm

TO FIND:

• What is the length of the diagonal of the rectangle ?

SOLUTION:

Let the diagonal of the rectangle be 'x' cm

We know that the formula for finding the diagonal of rectangle is:-

$\large{\boxed{\bf{\star \: (DIAGONAL)^2 = (BASE)^2 + (PERPENDICULAR)^2 \: \star}}}$

According to question:-

• Perpendicular = 14 cm
• Base = 48 cm

On putting the given values in the formula, we get

$\sf{\longmapsto (x)^2 = (48)^2 + (14)^2 }$

$\sf{\longmapsto x^2 = 2304 + 196 }$

$\sf{\longmapsto x^2 = 2500}$

$\sf{\longmapsto x = \sqrt{2500} }$

$\bf{\longmapsto x = 50 \: cm }$

• DIAGONAL = x = 50 cm

❝ Hence, the diagonal of the rectangle is 50 cm ❞

______________________

Answer 2

Given ,

• The dimensions of rectangle are 48 cm and 14 cm

Let ,

• The length of diagonal of rectangle be " x "

By pythagoras theorem ,

(x)² = (48)² + (14)²

(x)² = 2304 + 196

(x)² = 2500

x = √2500

x = 50 cm

$\sf \therefore \underline{The \: length \: of \: diagonal \: of \: rectangle \: is \: 50 \: cm}$