Question

the dimensions of a rectangle whose length is twice of breadth and it's perimeter equal to 180 CM are​

Answer 1

$\huge\underline{SOLUTION}$

$\huge{Given}$

Perimeter of the Rectangle = 180cm

$\large{ACCORDING\:TO\:QUESTION}$

Length is twice of breadth.

So, Breadth = x ; Length = 2x

$\large{FORMULA}$

Perimeter of RECTANGLE = 2 (l + b)

$\large{By\:Applying\:Formula}$

==> 2 (l + b) = 180

==> 2 (2x + x) = 180

==> 2 × 3x = 180

==> 6x = 180

==> x = 180/6

==> x = 30

$\large{Therefore}$

Breadth of the rectangle(x) = 30cm

Length of the rectangle (2x) =2×30 =60cm

Answer 2

Answer:

Breadth is 30 cm amd length is 60 cm.

Step-by-step explanation:

Calculation:2×(l+b)

=[2×(2x+x)] cm [Since let breadth be x cm and length 2x cm as it is twice of breadth]

=(2×3x )cm

=6x cm

Therefore perimeter as given in the question =180

A.T.P.;

6x=180

=> x = 180/6

.

. . X = 30

The value of x is 30 cm and lenght is 60 cm as it is twice of breadth.

VERIFICATION :

Perimeter is 2 ×(l+b) = 2 × ( 30 + 60 ) cm = (2×90) cm = 180 cm.