Question

The dimensions of a rectangular field are 25 m and 16.4 m. Two paths run parallel to the sides
of the rectangle through the centre of the field. The width of the paths is 1.7 m respectively. Find
the area of the paths.​

Answer 1

Length of rectangular field, l=25m

Width of rectangular field, b=16.4m

Length of the shorter path, l

1

=16.4m

Width of the shorter path, b

1

=2m

Length of the longer path, l

2

=25m

Width of the longer path, b

2

=1.7m

Area of shorter path, A

1

=l

1

×b

1

=(16.4×2)m

2

=32.8m

2

Area of longer path, A

2

=l

2

×b

2

=(26×1.7)m

2

=42.5m

2

Thus, Area of the path, P=A

1

+A

2

−Area of common path

=(32.8+42.5)m

2

−(2×1.7)m

2

=75.3m

2

−3.4m

2

=71.9m

2

Area of the rectangular field, A=l×b

=(25×16.4)m

2

=410m

2

Hence area of the remaining position of the field.

=A−P

=(410−71.9)m

2

=338.1m

2

.