Question

The dimensions of a rectangular field are 25m and 16.4m. Two paths run parallel to the sides of the rectangle through the centre of the field. The width of the paths is 1.7m, respectively. Find the area of the paths​

Answer 1

Answer:

Step-by-step explanation:

Length of rectangular field, l=25m

Width of rectangular field, b=16.4m

Length of the shorter path, l  

1

​

=16.4m

Width of the shorter path, b  

1

​

=2m

Length of the longer path, l  

2

​

=25m

Width of the longer path, b  

2

​

=1.7m

Area of shorter path, A  

1

​

=l  

1

​

×b  

1

​

 

=(16.4×2)m  

2

 

=32.8m  

2

 

Area of longer path, A  

2

​

=l  

2

​

×b  

2

​

 

=(26×1.7)m  

2

 

=42.5m  

2

 

Thus, Area of the path, P=A  

1

​

+A  

2

​

−Area of common path

=(32.8+42.5)m  

2

−(2×1.7)m  

2

 

=75.3m  

2

−3.4m  

2

 

=71.9m  

2

 

Area of the rectangular field, A=l×b

=(25×16.4)m  

2

 

=410m  

2

 

Hence area of the remaining position of the field.

=A−P

=(410−71.9)m  

2

 

=338.1m  

2

.