Question

The dimensions of a rectangular field are 90m and 60 m . Two roads are constructed such that they cut other at the centre of the field and are parallel to its sides . If the width of each road is 3m , find -

(I) The area covered by roads .

(2) The cost of constructing the roads at rate of ₹110 per m*2
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Answer 1

Step-by-step explanation:

The answer is in the above attachment

Answer 2

Given:-

Length of Rectangular field = 90m

Breadth of Rectangular field = 60m

Width of road at centre = 3m

Need To Find:-

Area of Roads

cost of constructing the roads at the rate of ₹110 per m².

Where:-

L denotes Length

B denotes Breadth

Explanation:-

[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.

$\:$

Solution:-

PQ = 3m ; QR = 60m

EF = 90m ; FG = 3m

KL = 3m

⠀⠀

Area of Rectangular Road = QR × PQ

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²

Hence, Area of Rectangular road is 180m2

∴Hence,AreaofRectangularroadis180m2

⠀⠀

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Now, We have to find the area Rectangular road EFGH.

Area of Rectangular road EFGH = L × B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²

Hence, Area of Rectangular road is 270m^2

∴Hence,AreaofRectangularroadis270m2