Question

The dimensions of a rectangular field is 25m× 164 m. It has two roads through its centre, running paralle to its sides. The width of the longer and shorter roads are 1.7 m and 2 m respectively. Find the total area of the roads and the area of the remaining portion of the field​

Answer 1

Answer:

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Step-by-step explanation:

Length of rectangular field, l=25m

Width of rectangular field, b=16.4m

Length of the shorter path, l

1

=16.4m

Width of the shorter path, b

1

=2m

Length of the longer path, l

2

=25m

Width of the longer path, b

2

=1.7m

Area of shorter path, A

1

=l

1

×b

1

=(16.4×2)m

2

=32.8m

2

Area of longer path, A

2

=l

2

×b

2

=(26×1.7)m

2

=42.5m

2

Thus, Area of the path, P=A

1

+A

2

−Area of common path

=(32.8+42.5)m

2

−(2×1.7)m

2

=75.3m

2

−3.4m

2

=71.9m

2

Area of the rectangular field, A=l×b

=(25×16.4)m

2

=410m

2

Hence area of the remaining position of the field.

=A−P

=(410−71.9)m

2

=338.1m

2

.