Question

The dimensions of a rectangular park are 100 m by 90 m. A path 5 m wide runs inside it along its boundary. Find the area of the path .

Answer 1

area of rectangle 100*90 is 9000m square

inner length is 100-2*5

100-10is 90 m

inner breadth is 90-2*5 is 90-10

80 m

inner area is 90*80 is 7200.

area of the path is 9000-7200

is 1800

so area of the path is 1800 m square

I Hope it will help.

Answer 2

Answer:

The area of the path is 1800 m².

Step-by-step explanation:

Consider the diagram below.

The area of the path is the difference between the area of rectangle ABCD and UVWX.

The dimension of rectangle ABCD are:

Length = l₁ = 100 m

Breadth = b₁ = 90 m

The dimension of rectangle UVWX are:

Length = l₂ = 100 - 10 = 90 m

Breadth = b₂ = 90 - 10 = 80 m

The area of a rectangle is: $Area=l\times b$

Compute the area of rectangle ABCD as follows:

$Area\ of\ ABCD=l_{1}\times B_{1}=100\times90=9000\ m^{2}$

Compute the area of rectangle UVWX as follows:

$Area\ of\ UVWX=l_{2}\times B_{2}=90\times80=7200\ m^{2}$

Compute the area of the path as follows:

$Area\ of\ path=Area\ of\ ABCD-Area\ of\ UVWX\\=9000-7200\\=1800\ m^{2}$

Thus, the area of the path is 1800 m².