Math, asked by GovindKrishnan, 1 year ago

The dimensions of a room are 13m x 8m x 5m. How long an iron rod can be placed?

Explain with complete calculations & justifications.

Answers

Answered by mysticd
40
let dimensions of the room
l= 13m, b=8m , h=5m
length of the long pipe = lengh of diagonal
=√l²+b²+h²
= √(13)²+8²+5²
=√169+64+25
=√258 m

GovindKrishnan: Thanks for helping! ☺
Anonymous: wlcm
mysticd: :)
Answered by Anonymous
30
Dimension of room =13×8×5

so longest rod that can be placed in the room is along it's diagonal.

diagonal of room = √ (l^2 + b^2 + h^2)

= √[ (13)^2 + 8^2 +5^2]

= √[169 +64 +25]

= √ 258

=16.062 m (approx.)

Anonymous: hope it helps govind
GovindKrishnan: Thanks for helping! ☺
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