The dimensions of a room are 13m x 8m x 5m. How long an iron rod can be placed?
Explain with complete calculations & justifications.
Answers
Answered by
40
let dimensions of the room
l= 13m, b=8m , h=5m
length of the long pipe = lengh of diagonal
=√l²+b²+h²
= √(13)²+8²+5²
=√169+64+25
=√258 m
l= 13m, b=8m , h=5m
length of the long pipe = lengh of diagonal
=√l²+b²+h²
= √(13)²+8²+5²
=√169+64+25
=√258 m
GovindKrishnan:
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Answered by
30
Dimension of room =13×8×5
so longest rod that can be placed in the room is along it's diagonal.
diagonal of room = √ (l^2 + b^2 + h^2)
= √[ (13)^2 + 8^2 +5^2]
= √[169 +64 +25]
= √ 258
=16.062 m (approx.)
so longest rod that can be placed in the room is along it's diagonal.
diagonal of room = √ (l^2 + b^2 + h^2)
= √[ (13)^2 + 8^2 +5^2]
= √[169 +64 +25]
= √ 258
=16.062 m (approx.)
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