Question

The dimensions of a room are 15 m and 10 m. Half the area of the room is to be covered
and half with white tiles. The lengths of blue and white tiles are 15 cm and 20 cm, respectives and
the breadths of blue and white tiles are 10 cm and 15 cm respectively. Find the number of tiles orage
colour required to cover the room.
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Answer 1

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Answer 2

Correct Question:

The dimensions of a room are 15 m and 10 m. Half the area of the room is to be covered with blue tiles and half with white tiles. The lengths of blue and white tiles are 15 cm and 20 cm, respectively and  the breadths of blue and white tiles are 10 cm and 15 cm respectively. Find the no. of tiles of each colour required to cover the room.

⇒ Given:

Dimensions of the room = 15 m x 10 m

Dimensions of the blue tile = 15 x 10 cm

Dimensions of the white tile = 10 x 15 cm

⇒ Analysis:

The first thing to be found in this question is to find the area of the room. It is given that half of the floor needs to be covered with blue tiles. Therefore, we need to find the half of the area of the floor and then divide it with the area of one blue tile. This will give us the number of blue tiles.

Next, we will have to find the area of one white tile and divide it from the area of the floor left. From this, we will get the number of white tiles required.

⇒ Formula to be used:

→ $\boxed{\sf{Area\:of\:rectangle=length\times\:breadth}}$

→ $\boxed{\sf{1\:m^2=10000\:cm^2}}$

⇒ Solution:

✳ The room:

Length of the room = 15 m

Breadth of the room = 10 m

Area = length x breadth

= 15 x 10

= 150 m²

We know that:

1 m² = 10000 cm²

So,

150 m² = 150000 cm²

✳ The blue tile:

Length of the tile = 15 cm

Breadth of the tile = 10 cm

Area = length x breadth

= 15 x 10

= 150 cm²

✳ The white tile

Length of the tile = 20 cm

Breadth of the tile = 15 cm

Area = length x breadth

= 20 x 15

= 300 cm²

Area to be covered with blue tiles:

= Half of the area of the room

= $\sf{\dfrac{150000}{2}}$

= 75000 cm²

No.  of blue tiles required:

$\sf{=\dfrac{Area\:of\:floor}{Area\:of\:1\:blue\:tile}}$

$\sf{=\dfrac{75000}{150}}$

= 500 tiles

The number of blue tiles required is 500.

Area to be covered with white tiles:

= The other half of the room

= 75000 cm²

No. of white tiles required:

$\sf{=\dfrac{Area\:of\:floor}{Area\:of\:1\:white\:tile}}$

$\sf{=\dfrac{75000}{300}}$

= 250 tiles

The number of white tiles required is 250.

Therefore,

Blue tiles = 500

White tiles = 250