Question

The dimensions of a room are 8m X 4m X 2m. How long an iron rod can be placed?​

Answer 1

Answer:

length of the longest rod that can be placed = length of the diagonal of cuboid

diagonal of cuboid = √l² + b² + h²

$= \sqrt{ {8}^{2} + {4}^{2} + {2}^{2} } \\ = \sqrt{64 + 16 + 4} \\ = \sqrt{84} \\ = 2 \sqrt{21}$

so, the length of the longest rod = 2√21 m.

Answer 2

Answer:

dimensions of room ;

l = 8m

b =4m

h =2m

longest rod would be the diagonal

d= l²+b²+h²

d=8²+4²+2²

d=64+16+4

d=84

d=2×2×3×7

d=2.21m