The dimensions of a solid iron cuboid are 4.4 m × 2.6 m × 1.0 m. It is melted
and recast into a hollow cylindrical pipe of 30 m inner radius and
thickness 5cm. Find the height of the pipe.
Answers
Answered by
0
Step-by-step explanation:
ANSWER
Iron : l=44m
b=2.6m
h
1
=1.0m
Hollow cylinder : r
1
=30cm=0.3m
r
2
=35cm=0.35m
h
2
=?
Volume of cuboid = Volume of hollow cylinder
l×b×h
1
=πh
2
(r
2
2
−r
1
2
)
4.4×2.6×1=
7
22
×h
2
×[(
100
35
)
2
−(
100
30
)
2
]
10
44
×
10
26
=
7
22
×h
2
×
(100)
2
(35−30)(35+30)
=
7
22
×h
2
×
(100)2
5×65
∴h
2
=
10
44
×
10
26
×
22
7
×
5×65
100×100
∴h
2
=112m
hppe u will give me brainlest answer
Similar questions