Question

The dimensions of a solid iron cuboid are 4·4 m x 2·6 m x 1·0 m. It is
melted and recast into a hollow cylindrical pipe of 30 cm inner radius and
thickness 5 cm. Find the length of the pipe.

Answer 1

Ans.

Now, volume of the cuboid
= 4.4 × 2.6 × 1.0 m³
= 11.44 m³

30 cm = 0.3 m and 5 cm = 0.05 m

Volume of the cuboid = Volume of the cylindrical pipe

=> 11.44 = π × {(Out radius of the cylindrical pipe)² - (Inner radius of the cylindrical pipe)²} × length of the pipe

=> 11.44 = π × { (Inner radius + thickness)² - (Inner radius)²} × length of the pipe

=> 11.44 = π × { (0.3 + 0.05)² - (0.3)²} × length of the pipe

=> 11.44 = π × (0.35² - 0.3²) × length of the pipe

=> 11.44 = π × 0.0325 × length of the pipe

=> length of the pipe = 11.44 / (π × 0.0325)

=> length of the pipe = 111.04

Therefore, the length of the pipe

= 111.04 cm = 1.1104 m

Answer 2

Step-by-step explanation:

hope it helps..............