Question

The dimensions of a solid iron cuboid are 4.4m×2.6m×1.0m. It is melted and recast into a hollow cylindrical pipe of 30cm inner radius and thickness 5cm. Find the length of the pipe

Answer 1

Step-by-step explanation:

Volume of cuboid = 4.4 × 2.6 × 1 m3

Inner and outer radii of cylindrical pipe = 30 cm, 35 cm

Volume of material used = π/1002 (352 - 302) × h m3

= π/1002 × 65 × 5h m3

Now, volume of material used = volume of cuboid

π/1002 × 65 × 5h = 4.4 × 2.6

h = 112 m

Answer 2

Answer:

vol. of Cuboid=4.4x2.6x1=11.44m3

cylindrical pipe=r=o. 30m

...... R=0.30+0.05=0.35

vol=πh (R+r) t = 22/7 h(0.35 +0.30) x 0.05=11,44

h = 11.44x7/22x0.65x0.05=112m

.length h =112m