Question

The dimensions of a solid iron cuboid are 44 m 26 m 10 m. It is melted and recast into a hollow cylindrical pipe of 30 cm inner radius and thickness 5 cm. Find the length of the pipe.

Answer 1

Answer:

Internal radius, r = 30 cm Thickness, w = 5 cmExternal radius, R = 30 + 5 = 35 cm Here volume of cuboid = volume of hollow cylinder 440 × 260 ×100 = π(R2 – r2)h ⇒ 440 × 260 × 100 = π(352 – 302)h ⇒440 × 260 × 100 = π(325)h ∴ h = 11200 cm = 112m