Math, asked by vekatrajalalshmi06, 4 months ago

The dimensions of an open box are 52 cm, 40 cm and 29 cm. Its thickness is 2 cm. If 1 cm^3 of metal used in the box weighs 0.5 gms, the weight of the box is :
(A) 8.56 kg
(B) 7.76 kg
(C) 7.576 kg
(D) 6.832 kg​

Answers

Answered by Maryjn
10

Answer:

D. 6.832 kg

Step-by-step explanation:

Since the box is an open one, we have :

Internal length = (52 - 4) cm = 48 cm

Internal breadth = (40 - 4) cm = 36 cm

Internal depth = (29 - 2) cm = 27 cm

Volume of the metal used in the box :

= External volume - Internal volume

= [(52 × 40 × 29) - (48 × 36 × 27)] cm³

= (60320 - 46656) cm³

= 13664 cm³

∴ Weight of the box :

=(13664×0.51000) kg

=6.832 kg

Answered by utkarshsingh076
1

Answer:

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