Physics, asked by Ambivert2802, 1 year ago

The dimensions of α/β in the equation F= α-t^2/βv^2,where F is the force,v is velocity and t is time, is
(1)[MLT^-1]
(2)[ML^-1T^-2]
(3)[ML^3T^-4]
(4)[ML^2T^-4]

Answers

Answered by aakashsinghal9756
18
dimension of f is MLT-2
so dimension of a/b =[MLT^-2][ML^-1]^2[T^-1]^2
=[ M^3L^-1T^4]
Similar questions