The dimensions of magnetic field in M, L, T and C (coulomb)
are given as
(a) [MLT⁻¹ C⁻¹] (b) [MT² C⁻²]
(c) [MT⁻¹ C⁻¹] (d) [MT⁻² C⁻¹]
Answers
Answered by
2
Answer:
Option C
Explanation:
Force F acting on charge q moving with velocity v in magnetic field B is given as F=qvB thus B=F/qv
∴[B]=[F]/[qv]=MLT^−2C×LT^−1=[MT^−1C^−1]
MARK IT BRAINLIEST PLZ,IF YOU GET HELP
Similar questions