Physics, asked by zain1387, 8 months ago

The dimensions of magnetic field in M, L, T and C (coulomb)
are given as
(a) [MLT⁻¹ C⁻¹] (b) [MT² C⁻²]
(c) [MT⁻¹ C⁻¹] (d) [MT⁻² C⁻¹]

Answers

Answered by brainlyuser00732
2

Answer:

Option C

Explanation:

Force F acting on charge q moving with velocity v in magnetic field B is given as F=qvB thus B=F/qv

∴[B]=[F]/[qv]=MLT^−2C×LT^−1=[MT^−1C^−1]

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