Question

The dimensions of pressure, [P]=[LxMyT2].what will be values of x,y,z?​

Answer 1

Answer:

P=F/A

=kgms-² x m-²

=kgm-¹s-²

the dimensions are as,

=[ML-¹T-²]

Answer 2

Answer:

x = -1 , y = 1

Explanation:

Pressure (P) = Force / Area . . . . . (1)

Since, Force = Mass × Acceleration

And, acceleration = velocity / time = [L T-1] / [T] = [L T-2]

∴ The dimensional formula of force = [M] × [L T-2] = Force = M1 L1 T-2 . . . . (2)

The dimensional formula of area = M0 L2 T0 . . . . (3)

On substituting equation (2) and (3) in equation (1) we get,

Pressure (P) = Force / Area

Or, P = [M1 L1 T-2] / [L2] = [M1 L-1 T -2].

∴ Dimension of Pressure = [M1 L-1 T -2]

"HOPE IT HELPS"