Math, asked by Shashibaid9930, 9 months ago

The dimensions of solid piece of iron are 1.5m×1m×50cm. Find the weight of iron if 1 cm iron weights 8 grams.

Answers

Answered by Ajinkya007
0

Answer:

Step-by-step explanation:

Shape of a rectangular solid is

cuboid,

Dimensions of the cubiod is

Length = l = 1.05 m

l = 1.05 × 100 cm = 105 cm

Breadth = b = 70 cm

Height = h = 1.5 cm

Volume of the solid = lbh

V = 105 cm × 70cm × 1.5 cm

V = 11025 cm³

According to the problem given,

1 cm³ iron weighs 8 grams

11025 cm³ iron weighs = 8 ×11025 gm

= 88200grams

= 88200/1000kg

=88.2kgs

Therefore,

Solid weighs 88.2 kgs

I hope this helps you.

:)

Answered by ShresthaTheMetalGuy
0

Answer:

Please mark as Brainliest answer

Step-by-step explanation:

Volume of iron piece=1.5×1×0.5=0.75m³

. or 7,50,000cm³

weight of 1cm³ of iron(given)=8g

weight of 7,50,000cm³ of iron=8×75×10⁴

total weight of solid iron=600×10⁴g

. or 60,00,000g or 6,000kg

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