Physics, asked by bhawnanarula7283, 10 months ago

The dimensions of the constant b in the vander waals gas equation are that of

Answers

Answered by saloni766
0

Answer:

The dimensions of 'a' in Vanderwaal's equation (P+V2a)(V−b)=RT is: (V-volume, P-Pressure, R-Universal gas constant, T- Temperature) A .

I hope it will help you...

Answered by VaibhavSR
0

Answer: Dimension of b= [M^{0} L^{3} T^{0}]

Explanation:

  • The Vander waal's equation is (p+\frac{a} {V^{2} })(V-b)=RT
  • We can only add and subtract quantities if they have the same dimensions so dimension of b will be same as dimension of V.
  • So, we know the dimension of volume is L^{3}.
  • Hence, the dimension of b in the above equation is   L^{3}.

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