Question

The dimensions of the floor of a mini auditorium are 30mx24m. If the

sum of the area of the floor and the ceiling is equal to the sum of the

areas of four walls. What is the volume of the hall? (class 8)

​

Answer 1

Answer:

area of the floor=30m×24 m=720 sq m

area of the celling= 720 sq m

so area of the 4 walls=(720+720) sqm=1440 sq m

2(length+breadth)×height=1440

=> 2(30+24)×height=1440

=> height=1440/108=160/12=40/3

so height=40/3 m

volume=length×breadth×height

=30×24×40/3 cu m

=9600 cu m

Answer 2

Answer:

the volume of the room is 9600m³

Step-by-step explanation:

Dimensions of the floor = 30m x 24m (L* B)

Let the length be 30m and breadth be 24m. let the height of the room be H

Given that the area of floor + area of ceiling = Area of 4 walls

=>  L*B + L*B = 2( B*H + L*H)

=> 2LB = 2BH + 2LH

=> 2LB = 2H( B + L)

=> 2*30*24 = 2H(30+24)

=> 1440 = 2H(54)

=> H = 1440/(2*54)

=> H = 40/3 = 13.333m

We need to find the volume of the hall.

We know that volume = length * breadth * height

                                     = 30 * 24 * (40/3)

                                     = 9600m³

Therefore the volume of the room is 9600m³