Question

The dimensions of the floor of a rectangular hall 8 m into 3M the floor of the whole is to be dried fully with 8 cm into 6 and rectangular tiles without breaking tiles to smaller size find the number of required tiles

Answer 1

area of rectangle = l×b
convert m in cm =8m:800 and 3m:300
area of hall =l×b
=800×300
=240000 sq cm
area of a tile =l×b
=8×6
=48 sq cm



no. of tiles required =240000÷48
=5000





therefore, 5000 tiles are required

Answer 2

$\tt ฏGIVEN:−$

$\tt length \: of \: floor = 4m =400cm$

$\tt breadth\: of \: floor= 3m = 300cm$

$\tt length\: of \: single \: tile= 8cm$

$\tt breadth\: of \: single \: tile= 6cm$

$\tt ฏFIND:-$

$\tt no. \: of \: tiles \: reqire = ?$

$\tt ฏSOLUTION:-$

$\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}$

$\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}$

$\tt now \: let \: no. \: of \: tiles = x$

$\tt = > area \: of \:hall= x\times area \: of \: each$

$\tt = > 120000 = x(48)$

$\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500$

$\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}$