Math, asked by parmjeetkaurgng1627, 1 year ago

The dimensions of the floor of a rectangular hall is 4 m into 3m the floor of a hall is to be dial fully with 88 cm into 6m rectangular tiles without breaking tiles to smaller size find the tile number of tiles required


brian5674: it is impossible because the dimensions of hall are 2m×3m and dimensions of tiles are 88cm × 6m, now you think how could a tile 6m long can fit in hall 3m......

Answers

Answered by ayu2945
2
I think you shuld first area of the hall and then area of tiles then divide hall by tiles you will get answer my friend.

Just try it.
Answered by Anonymous
0

\tt ฏGIVEN:−

\tt length \: of \: floor = 4m =400cm

\tt breadth\: of \: floor= 3m = 300cm

\tt length\: of \: single \: tile= 8cm

\tt breadth\: of \: single \: tile= 6cm

\tt ฏFIND:-

\tt no. \: of \: tiles \: reqire = ?

\tt ฏSOLUTION:-

\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}

\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}

\tt now \: let \: no. \: of \: tiles = x

\tt = > area \: of \:hall= x\times area \: of \: each

\tt = > 120000 = x(48)

\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500

\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}

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