The dimensions of the outer angle at the 3 vertices of a triangle are
(2x+30)°, (3x-10)°, 100° If so, look at the value of x.
Can you tell me the correct answer as soon as possible?
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Answers
Answered by
0
we know that outer angle sum is 180
So,
2x+30+3x-10+100=180
2x+3x+30-10=180-100
5x+20=80
5x=80-20
5x=60
x=60/5
x=12
Answered by
2
Answer:
sum of outer angles =180°
(2x+30)+(3x-10)+100=180
2x+30+3x-10=180-100
5x+20=80
5x=80-20
5x=60
x=60/5
x=12
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