The dimensions of the sides of a parallelogram are 51 cm and 35 cm. If one of its diagonals measures 20 cm 0 三 Find the area of the quadrilateral along that parallelogram.
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1
Step-by-step explanation:
Consider AB=51cm, BC=37cm and AC=20cm.
In ΔABC,
s=
2
a+b+c
=
2
51+37+20
=54
The area of ΔABC is,
A=
s(s−a)(s−b)(s−c)
=
54(54−51)(54−37)(54−20)
=
54(3)(17)(34)
=
93636
=306cm
2
The area of parallelogram is the twice of ΔABC,
A=2×306
A=612cm
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