Physics, asked by deepikaratwani48, 1 year ago

The dimensions of (ue⁰)^-½ are
u= mew
e⁰= permitivity of free space​

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Answered by azeemramkhan
0

Answer:

Explanation:

e°=[M^-1 L^-3 T^4 A^2]

u=[MLT^-2 A^-2]

Then, 1/✓(ue°)=1/✓(M^-1 L^-3 T^4 A^2).(MLT^-2 A^-2)

=[LT^-1]

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